Grade 11 Math Notes

 Grade 11

Math I

Capter 1

Remainder Theorem and Factor Theorem

1.1 Dividing Polynomials

1.2 Synthetic Division 

Long and Synthetic Division

1.3 Remainder Theorem Pg. 



Remainder and Factors

1.4 Factor Theorem Pg. 7

1.4 Factor Theorem Pg. 7 

Theorem 1.3


Notes - No. Of Factors


Theorem 1.4 &1.5


Notes & Example

Possible Rational Roots 

Binomial (Direct Solve) and 

Polynomial (1St Rational Root step by step still to be binomial)


Notes & Example 

Constant Term, 

Leading Coefficient, 

How to do possible rational roots, and 

rational roots in lowest term

Part 1

Part 2

Part 3 

Lowest Term

Finding Factors of Polynomials by rational roots to get binomial for final solution


Thinking Process for No.6 from Ex 1.2


Guides for findinf two unknown coefficients


Chapter 2 

The Binomial Theorem Pg.15

Binomial Expansion

Coefficient Pacterm



Example 1


2.2 The Binomial Theorem Pg.17 

Power Level and Solution

Combinatorial Coefficient

Theorem 2.1 Pg.18


Collorary 2.2 Pg.18





General Term of (x+y)n

Chapter (11) 

Methods of Differentiations

👉Consider real-valued functions whose domains arbitrary subset of R. 

👉Limit of a function and derivatives 

👉sun rule, different rule, product rule, quotient rule, and chain rule (To calculate derivative more effeciently) 

👉Method of Differentiation for implicit functions 

👉Undifined (Limit) (My opinion - Asymtope) and Value (Continue)

👉If any is divided by infinity, result is always "0". eg. 6/ꟹ, 9/ꟹ
👉Rational Function, Divide x as power of x in denorminator to both of denorminator and upper part and continue solve as usual. If denorminator is "0", it is undefined.
👉Square Root function, negative is undefined.
👉Simple Plynomial Function, Multiply the highest powered x to the whole polynomial and solve continue as usual.

Easy Notes for Chapter 11

Methods of Differentiation

From the Myanmar Grade 11 Mathematics Textbook

Chapter 11 mainly teaches:

  1. Limits of Functions
  2. Derivatives
  3. Differentiation Rules
  4. Implicit Differentiation

11.1 Limit of Functions

Simple Idea

A limit means:

“What value does a function approach when 
xx

Example:

If

f(x)=x+2

when 
x3x\to 3
,

f(x)5

because:

3+2=5




 

Basic Notation

limxaf(x)
means:

“the limit of f(x) as  approaches a.

Example 1

Find:

limx2(x2+3)

Substitute x=2:

22+3=4+3=7

Answer: 7

Important Idea

A limit helps us find the instantaneous rate of change, which leads to derivatives.


11.2 Derivatives

Meaning of Derivative

Derivative shows:

  • how fast something changes
  • slope of a curve
  • gradient at a point

Symbol:

dydx​

or

f(x)


Derivative Formula

f(x)=limh0f(x+h)f(x)hf'(x)=\lim_{h\to 0}\frac{f(x+h)-f(x)}{h}

This is the basic definition of differentiation.


Example 2

Find derivative of:

f(x)=x2

Using rule:

ddx(x2)=2x

Answer: 2x


11.3 Differentiation Rules

These rules are very important.


1. Constant Rule

If cc is a constant:

ddx(c)=0\frac{d}{dx}(c)=0

Example:

ddx(7)=0


2. Power Rule

ddx(xn)=nxn1\frac{d}{dx}(x^n)=nx^{n-1}

Examples:

ddx(x3)=3x2ddx(x5)=5x4


3. Constant Multiple Rule

ddx[cf(x)]=cddx[f(x)]\frac{d}{dx}[cf(x)]=c\frac{d}{dx}[f(x)]

Example:

ddx(5x2)=5(2x)=10x\frac{d}{dx}(5x^2)=5(2x)=10x----------------------------------------------------------------------------------------------------------------------

4. Sum Rule

ddx[f(x)+g(x)]=f(x)+g(x)

Example:

ddx(x2+3x)=2x+3


5. Difference Rule

ddx[f(x)g(x)]=f(x)g(x)

Example:

ddx(x24x)=2x4


6. Product Rule

Used when two functions multiply.

ddx(uv)=udvdx+vdudx\frac{d}{dx}(uv)=u\frac{dv}{dx}+v\frac{du}{dx}

Example:

Find derivative of:

y=x2(x+1)

Let

u=x2,v=x+1

Then:

dudx=2x\frac{du}{dx}=2x
dvdx=1\frac{dv}{dx}=1

Apply rule:

dydx=x2(1)+(x+1)(2x)\frac{dy}{dx} = x^2(1)+(x+1)(2x)
=x2+2x2+2x=x^2+2x^2+2x
=3x2+2x

Answer:

3x2+2x​


7. Quotient Rule

Used for division.

ddx(uv)=vdudxudvdxv2\frac{d}{dx}\left(\frac{u}{v}\right)=\frac{v\frac{du}{dx}-u\frac{dv}{dx}}{v^2}

Example:

y=x2x+1y=\frac{x^2}{x+1}

Use quotient rule.

----------------------------------------------------------------------------------------

11.4 Implicit Differentiation

Sometimes
y
is mixed with
x
.

Example:

x2+y2=25

Differentiate both sides.

ddx(x2)+ddx(y2)=0\frac{d}{dx}(x^2)+\frac{d}{dx}(y^2)=0
2x+2ydydx=0

Solve:

2ydydx=2x2y\frac{dy}{dx}=-2x
dydx=xy\frac{dy}{dx}=-\frac{x}{y}

Answer:

dydx=xy


Short Tricks to Remember

RuleShortcut
ConstantAnswer is 0
xnx^n
Bring power down
AdditionDifferentiate separately
MultiplicationProduct Rule
DivisionQuotient Rule
Mixed yx,yImplicit Differentiation

Important Formulas Summary

Power Rule

ddx(xn)=nxn1\frac{d}{dx}(x^n)=nx^{n-1}

Product Rule

ddx(uv)=udvdx+vdudx\frac{d}{dx}(uv)=u\frac{dv}{dx}+v\frac{du}{dx}

Quotient Rule

ddx(uv)=vdudxudvdxv2\frac{d}{dx}\left(\frac{u}{v}\right)=\frac{v\frac{du}{dx}-u\frac{dv}{dx}}{v^2}


Exam Tips

  • Learn formulas by heart.
  • Practice many differentiation problems.
  • Simplify answers carefully.
  • Watch signs (+ and −).
  • Write steps clearly in exams.

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