Grade 10 Physics Solutions

 Grade 10

Physics

Solutions

Chapter 2

Motion

                     No.2 (Pg.22)                                                        

No.3

No.4

No.5 (Pg.22)

No.6 (Pg. 22)

No.8 (Pg.23)

No.9 (Pg. 23)

No.10 (Pg.23)

No. 11

No. 12

No. 13

No. 14

No. 15

No. 16

No. 17

No. 18

Chapter 3

FORCE 

Example 1 & 2

Example 3

Review Exercise (Pg-29)

Review Exercise (Pg-30)

Review Pg. 32

Example 5, Pg. 32

Example 5, Solutions

Example 6, Pg. 33

Example 6, Solutions

Example 7, Pg. 33

Example 7, Solutions

Review (Pg. 34)

Exercise no.​1&2

Exercise no. 3

Exercise no. 4

Exercise no. 5

Exercise no. 6

Exercise no. 7

Exercise no. 8

Exercise no. 9

Exercise no. 10

Exercise no. 11

Exercise no. 12

Exercise no. 13 

Notes -​ First, calculate hight in one way and after that, result is multiplied by 2 to get total whole distance. 

Exercise no. 14 

Notes -​ Given hight 40 m does not mean it is highest point. So at a high level, a stone can be seen two time in a eye level as upward and falling. In the sum, a stone can be seen at upward 2s and falling 4s.

Exercise no. 15

Notes -​ Similar to No. 13, First, calculate hight in one way and after that, result is multiplied by 2 to get total whole distance. 

Exercise no. 16

Exercise no. 17

Law of Conservation of Momuntem (Collisio) There are one object with velocity and another object with stability before collision and both with velocities after collision. 

Exercise no. 18 

Law of Conservation of Momemtun 

There are two objects with stability before collision and them with velocities after collision. So two methods can be used in solution. 

1. One method is that total momentum before collision = total momentum after collision. 

2. Another method is that one side only after collision is used. After collision, Momentum of one object = momentum of another can be directly used without thinking stable conditions before collision. 

Notes - recoil velocity of boat is in opposite direction and is minus sign.